What is the order of constructor call when the object of derived class B is declared?

I must add to the previous answers because everyone seems to be ignoring it

When you have a derived class instance being created, it is true that the code inside the constructor of the base will be called before the code inside the constructor of the derived, but keep in mind that the derived is still technically "created" before the base.

And when you have the derived class destructor being called, it is true that the code inside the derived destructor is called before the code inside the base destructor, but also keep in mind that the base is destroyed before the derived.

When I am saying created/destroyed I am actually referring to allocated/deallocated.

If you look at the memory layout of these instances, you will see that the derived instance composes the base instance. For example:

Memory of derived: 0x00001110 to 0x00001120

Memory of base : 0x00001114 to 0x00001118

Therefore, the derived class must be allocated BEFORE the base in the construction. And the derived class must be deallocated AFTER the base in the destruction.

If you have the following code:

class Base 
{
public:
    Base[]
    {
        std::cout 
class Derived : T {
    using T::T;   // declare the constructors from T
    // ...
};

A deriving class can't inherit from multiple base classes if those base classes have constructors that have an identical signature.

Constructors and composite classes

Classes that contain class-type members are known as composite classes. When a class-type member of a composite class is created, the constructor is called before the class's own constructor. When a contained class lacks a default constructor, you must use an initialization list in the constructor of the composite class. In the earlier StorageBox example, if you change the type of the m_label member variable to a new Label class, you must call both the base class constructor and initialize the m_label variable in the StorageBox constructor:

class Label {
public:
    Label[const string& name, const string& address] { m_name = name; m_address = address; }
    string m_name;
    string m_address;
};

class StorageBox : public Box {
public:
    StorageBox[int width, int length, int height, Label label]
        : Box[width, length, height], m_label[label]{}
private:
    Label m_label;
};

int main[]{
// passing a named Label
    Label label1{ "some_name", "some_address" };
    StorageBox sb1[1, 2, 3, label1];

    // passing a temporary label
    StorageBox sb2[3, 4, 5, Label{ "another name", "another address" }];

    // passing a temporary label as an initializer list
    StorageBox sb3[1, 2, 3, {"myname", "myaddress"}];
}

In this section

  • Copy constructors and copy assignment operators
  • Move constructors and move assignment operators
  • Delegating constructors

See also

Classes and structs

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What is the order in which constructors are called when an object of a derived class is created?

The base class constructors are called in order of derivation—for example, if ClassA is derived from ClassB , which is derived from ClassC , the ClassC constructor is called first, then the ClassB constructor, then the ClassA constructor.

In what order are the class constructors and destructors called when a derived class object is created explain with the help of suitable program?

As constructor is the first function called by the compiler when an object is created and the destructor is the last class member called by the compiler for an object. If the constructor and destructor are not declared by the user, the compiler defines the default constructor and destructor of a class object.

In what order are constructors called?

When a class object is created using constructors, the execution order of constructors is: Constructors of Virtual base classes are executed, in the order that they appear in the base list. Constructors of nonvirtual base classes are executed, in the declaration order.

When a derived class object is created the constructor of the derived class is called first and then the base class constructor is called?

1 Answer. Best explanation: First the base class constructor is invoked. When we create a derived class object, the system tries to invoke its constructor but the class is derived so first the base class must be initialized, hence in turn the base class constructor is invoked before the derived class constructor.

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