The selling price of 16 spoon is equal to the cost price of 15 school find the loss percent
Rs_aggarwal Solutions for Class 7 Math Chapter 11 Profit And Loss are provided here with simple step-by-step explanations. These solutions for Profit And Loss are extremely popular among Class 7 students for Math Profit And Loss Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs_aggarwal Book of Class 7 Math Chapter 11 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs_aggarwal Solutions. All Rs_aggarwal Solutions for class Class 7 Math are prepared by experts and are 100% accurate. Page No 157:Answer:(i) CP = Rs. 950 SP ={(100 + Gain%)100× CP } = {(100 + 6)100× 950} = 106100× 950 = 100700100 = Rs. 1007 (ii) CP = Rs. 9600 SP={ (100 + Gain%)100× CP} = {(100 + 503)100× 9600} = 350300 ×9600 = 33603 = Rs. 11200 (iii) CP = Rs. 1540 SP={(100 - Loss%)100× CP} = {(100 - 4)100× 1540} = 96100× 1540 = 147840 100 = Rs. 1478.40 (iv) CP = Rs. 8640 SP={(100 - Loss%)100× CP} = {(100 - 252)100× 8640} = 175200× 8640 = 1512000200 = Rs. 7560 Page No 157:Answer:(i) CP = Rs. 2400 Gain% = GainCP × 100 = 1922400× 100 = 8 (ii) CP = Rs. 1650 Loss% = LossCP × 100 =1981650 × 100 = 12 (iii) CP = Rs. 12000 and SP = Rs. 12800 Gain% = GainCP × 100 = 80012000× 100 = 6.66 (iv) CP = Rs. 1800 Loss% = LossCP × 100 =1891800 × 100 = 10.5 Page No 157:Answer:(i) SP = Rs. 924 CP ={ 100(100 + Gain%)× SP} ={100(100 + 10)× 924} = 92400110 = Rs. 840 (ii) SP = Rs. 1755 CP = { 100(100 + Gain%)× SP} ={100(100 + 252)× 1755} = {200225× 1755} = 351000225 = Rs. 1560
(iii) SP = Rs. 8510 CP = {100(100 - Loss%)× SP} = {100(100 - 8 )× 8510} = 85100092= Rs. 9250
(iv) SP = Rs. 5600 CP = {100(100 - Loss %)× SP} = {100(100 - 203)×5600} = {300280 × 5600} = 16800028 = Rs. 6000 Page No 157:Answer:Cost price of an almirah = Rs. 13600 Gain% = GainCP× 100 % =280014000× 100% =2800140% = 20% Page No 157:
Answer:Cost price of the house = Rs. 765000 SP= {(100 + gain %)100× CP} = {(100 + 5)100× 880000} = 105100× 880000 = Rs. 924000 He gets Rs. 924000. Page No 157:Answer:CP of 12 lemons (dozen) = Rs. 25 CP of five lemons = 5 × 2512 = 12512 = Rs. 10.42 SP of five lemons = Rs. 12 (given) Gain = SP - CP = ( 12 - 10.42 ) = Rs 1.58 Gain% =GainCP × 100% =1.5810.42 × 100 % = 15.2% Page No 157:Answer:Let the cost price of the pen be Re 1. Gain% = GainCP× 100 % =312× 100 %= 25% Gain% = 25% Page No 157:Answer:Let the cost price of one spoon be Re 1. Loss% = LossCP× 100% = 116× 100 %=6.25% Loss% = 6.25% Page No 157:Answer:Cost price of a video = Rs. 12000 ={(100 + 10)100× 12000} = {110100× 12000} = Rs.13200 So, Rahul purchased at a cost price of Rs. 13200. Rahul sells it at a loss of 5%. SP of a video at loss of 5% = {(100 - Loss%)100× CP} ={(100 - 5)100× 13200} = 95100× 13200 = Rs. 12540 ∴ Rakesh pays = Rs. 12540 Page No 157:Answer:SP of the sofa set = Rs. 21600 CP of the sofa set={100(100 + Gain%)×SP} = {100(100 + 8)× 21600} = 2160000108 = Rs. 20000 He purchased it at the cost of Rs. 20000. Page No 157:Answer:SP of the watch = Rs 11400 CP = {100(100 - Loss% )× SP} ={100(100 - 5)× 11400} = 1140095 = Rs. 12000 He purchased it at the cost of Rs. 12000. Page No 157:Answer:SP of the calculator = Rs. 1325 CP of the calculator = {100(100 + Gain%)× SP} ={100(100 + 6)×1325} = 132500106 = Rs . 1250 SP of the calculator= {(100 + Gain%)100× CP} = {(100 + 12)100× 1250} = 140000100 = Rs.1400 Page No 157:Answer:SP of a computer = Rs. 24480 CP of the computer={100(100 - Loss%)× SP} = {100(100 - 4)× 24480} = 244800096= Rs. 25500 In
order to gain 4%: Page No 157:Answer:Let the CP of the tricycle be Rs. x SP at 15% gain = {(100 + Gain%)100× CP
} =Rs. 2320x SP at 20% gain = x × 120100 = Rs. 65x 65 x-2320x=108⇒24x-23x20=108⇒x20=108⇒x=2160 Hence, the cost price of the tricycle is Rs. 2160 Page No 157:Answer:Let CP of a television be Rs x. 106100x - 92100x = 3360 ⇒14100x = 3360 ⇒ x = 33600014 = 24000 ∴ CP = Rs. 24000 Page No 157:Answer:SP of each cycle = Rs. 2376 He looses 10% in the second cycle. =100(100 - 10)× 2376= 10090× 2376 = 237609 = Rs. 2640 Total CP = Rs. ( 2160 + 2640 ) = Rs. 4800
Page No 157:Answer:Let the CP of the exhaust fan be Rs. x. SP = Rs ( x + x6) SP = Rs. 7350 ∴ x + x6 = 7350 Page No 157:Answer:Mohit sold a watch to Karim at Rs. x.
But, Rahim pays Rs. 14300. ⇒x = 14300 × 25 × 10 26 × 11 =3575000286 =12500 Mohit purchased it at Rs. 25000. Page No 157:Answer:Let the production cost of a washing machine be Rs. x.
Profit of the retailer = 25% = Rs. ( 1110x × 2320×125100) = Rs. (1110x × 2320× 54) Given:
⇒x = 37950 × 10 × 20 × 411 ×
23 × 5 ∴ Production cost of a washing machine = Rs. 24000 Page No 157:Answer:Mr. Mehta purchased a video at the cost of Rs. 20000. He lost 5% on the video. SP= (100-Loss%)100×CP=100-5100×20000=95100×20000=Rs. 19000 He gained 8% on the television. SP= (100+Gain%)100×CP=100+8100×30000=108 100×30000=Rs. 32400 Total SP = Rs. ( 190000 + 32400 ) = Rs. 51400
Total CP = Rs. 50000 Page No 158:Answer:Let the CP of 1 orange be Rs. x. Loss = SP of 4 oranges = 4y (given) We know: Loss% = LossCP×100 % =4y 36x× 100 % =4 × 9x36x× 10× 100% = 10% Loss% = 10% Page No 158:Answer:Let the CP of one pencil be Rs. x. Gain = SP - CP ⇒12y=96y-96x⇒96x=96y-12y⇒96x=84y⇒x=84y 96 Gain% = GainCP×100 % =12y96x×100%=12y×9696×84y×100%=14.28% Page No 158:Answer:(b) 25% CP of the book = Rs. 80 Page No 158:Answer:(a) 1212% CP of a football = Rs. 120 CP>SP Page No 158:Answer:(b) 25% SP of the bat = Rs. 100 Gain = SP - CP Gain% = GainCP× 100 %=2080× 100% = 25% Page No 158:Answer:(a) Rs. 180 SP of the racket = Rs. 198 CP of the racket={100(100 + Gain %)× 100} = {100(100 + 10)× 198} =100110× 198 = Rs. 180 Page No 158:Answer:Let the cost price be Rs. x. Given: ∴ 67x = 144 ∴ CP = Rs. 168 New SP = Rs. 189 Gain% = GainCP× 100%= 21168 × 100%=12.5% The correct answer is 12.5%. Page No 158:Answer:(d) Rs. 72 SP of the pen = Rs. 48 In order to gain 20%: SP = {(100 + Gain%)100× CP} = {(100 + 20)100× 60} = 120100× 60 = Rs. 72 Page No 158:Answer:(a) 20% Let the cost price of each pencil be Rs.1 Loss = CP - SP = Rs (15 -12) = Rs 3 Loss% = LossCP× 100 %= 315× 100% = 300 15%= 20% Page No 158:Answer:(d) 3313% Let the cost price of each toffee be Rs. 1 CP = Rs 3 Gain = SP - CP = Rs ( 4 - 3 ) = Re 1 Page No 158:Answer:(c) Rs. 176 SP of an article = Rs. 144 In order to gain 10%: S.P. = (100 + Gain%) 100× CP= (100 + 10)100× 160= 110100× 160= Rs . 176 Page No 159:Answer:(a) 50% CP of six lemons = Re 1 CP of four lemon = Rs 46 Gain
= 1 - 46 =26 = Rs 13 Page No 159:Answer:
(d)Rs. 600 SP of the chair = Rs 720 C.P. = {100(100 + Profit percentage)× S.P.} = {100120× 720} = 720012 = Rs. 600 Page No 159:Answer:(c) Rs. 700 SP of a stool = Rs 630 Page No 160:Answer:SP of the chair = Rs 1375 CP of the chair={100(100 + Gain%)× SP} ={100(100 + 10)× 1375} =137500110 = Rs. 1250 Page No 160:Answer:Let the cost of each pen be Rs. 1 Page No 160:Answer:Let the cost price of the fan be Rs. x. So, CP of the fan is Rs. 2350. Page No 160:Answer:Cost price of six lemons = Rs. 10 Gain = SP- CP=Rs. (15 - 13.33) = Rs. 1.67
Gain% = GainC.P.× 100 % Page No 160:Answer:SP of the bat = Rs 486 CP of the bat = Rs 540 Page No 160:Answer:(b) Rs 85 SP of a football = Rs 100 Page No 160:Answer:(c) 15.2% Cost price of 12 bananas = Rs. 25 He sells five
bananas at the cost (SP) of Rs. 12. = =Rs. (12 - 10.42) = Rs. 1.58 Gain% = GainCP× 100% = 1.5810.4× 100 %= 15.2% Page No 160:Answer:(c) Rs. 196 Let the cost price of the jug be Rs. x. SP of the jug = Rs 168 (given) ∴ 67x = 168 ∴ CP of the jug = Rs. 196 Page No 160:Answer:(c) 6623% Let the cost price of each banana be Re 1. Gain% = GainCP× 100% = 23× 100% = 2003 %= 6623% Page No 160:Answer:(i) Loss = (CP) - ( SP) (ii) CP = 100 × SP(100 + Gain%) (iii) Profit or loss is always reckoned on the cost price. Page No 160:Answer:(i) False (ii) True View NCERT Solutions for all chapters of Class 7 |