Giải bài tập vật lý đại cương 1 chương 3 năm 2024
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ĐIỆN HỌC CHƯƠNG 1: TRƯỜNG TĨNH ĐIỆN 1-1. Tìm lực hút giữa hạt nhân và electron trong nguyên tử Hyđrô. Biết rằng bán kính nguyên tử Hyđrô là 0,5.10-8 cm, điện tích của electron e = -1,6.10-19 C. Giải: Sử dụng công thức lực tương tác giữa hai điện tích của định luật Culông (với điện tích của electron và hạt nhân hyđrô qe \= - qp \= -1,6.10-19C, khoảng cách r = 0,5.10-10m): N10.23,9 )10.5,0( )10.6,1.(10.9 r qqk F8 210 2199 2 21 1-2. Lực đẩy tĩnh điện giữa hai proton sẽ lớn hơn lực hấp dẫn giữa chúng bao nhiêu lần, cho biết điện tích của proto là 1,6.10-19C, khối lượng của nó bằng 1,67.10-27 kg. Giải: Theo công thức của định luật Culông và định luật vạn vật hấp dẫn, ta có: 2 2 2 2 2 1r Gm Fvµ; r kq F )lÇn(10.25,1 )10.67,1.(10.67,6 )10.6,1.(10.9 Gm kq F F36 22711 2199 2 2 2 1 1-3. Hai quả cầu đặt trong chân không có cùng bán kính và cùng khối lượng được treo ở hai đầu sợi dây sao cho mặt ngoài của chúng tiếp xúc với nhau. Sau khi truyền cho các quả cầu một điện tích q0 \= 4.10-7C, chúng đẩy nhau và góc giữa hai sợi dây bây giờ bằng 600. Tính khối lượng của các quả cầu nếu khoảng cách từ điểm treo đến tâm quả cầu bằng l \= 20 cm. Giải: Do các quả cầu là giống nhau nên điện tích mỗi quả cầu nhận được là: Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. Why is this page out of focus?This is a Premium document. Become Premium to read the whole document. 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