How many words each containing 2 vowels and 3 consonants can be formed with the letters of dynamite?
Home Show
Índice
> English > Class 11 > Maths > Chapter > Permutations And Combinations > How many words, with or withou... Get Answer to any question, just click a photo and upload the photo and get the answer completely free, UPLOAD PHOTO AND GET THE ANSWER NOW! How many words, with or without meaning, each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER?Answer Verified Hint: Count the number of vowels and consonants in the word DAUGHTER. Let the counts be x, y respectively. The required words should have 2 vowels and 3 consonants in it. So the no. of words that contains 2 vowels and 3 consonants which can be formed from the letters of DAUGHTER is ${}^x{C_2} \times {}^y{C_3}$ Complete step-by-step answer: Note: A Permutation is arranging the objects in order. Combinations are the way of selecting the objects from a group of objects or collection. When the order of the objects does not matter then it should be considered as Combination and when the order matters then it should be considered as Permutation. Do not confuse using a combination, when required, instead of a permutation and vice-versa. Misc 1 - Chapter 7 Class 11 Permutations and Combinations (Term 2)Last updated at Jan. 13, 2022 by This video is only available for Teachoo black users Solve all your doubts with Teachoo Black (new monthly pack available now!) TranscriptMisc 1 How many words, with or without meaning, each of 2 vowels and 3 consonants can be formed from the letters of the word DAUGHTER? Number ways of selecting 2 vowels & 3 consonants = 3C2 × 5C3 = 3!/2!(3 − 2)! × 5!/3!(5 − 3)! = 3!/2!1! × 5!/3!2! = 30 Now, Each of these 5 letters can be arranged in 5 ways Number of arrangements = 5P5 = 5!/(5 − 5)! = 5!/0! = 5! = 5 × 4 × 3 × 2 × 1 = 120 Thus, Total number of words = Number of ways of selecting × Number of arrangements = 30 × 120 = 3600 How many different words each containing 2 vowels and 3 consonants can?=6800×120=816000. How many words can be formed each of 2 vowels and 3 consonants from the letters of the given word mathematics?Therefore, 30 words can be formed from the letters of the word DAUGHTER each containing 2 vowels and 3 consonants. Note: A Permutation is arranging the objects in order. How many words each containing 2 vowels and 3 consonants van be formed using 5 vowels and 8 consonants?So, total number of words = 5C2× 17C3×5! =816000. What is the total number of words formed by 2 vowels and 3 consonants taken from 4 vowels and 5 consonants?=60×120=7200. How many different words each containing 2 vowels and 3 consonants can?=6800×120=816000.
How many words can be formed each of 2 vowels and 3 consonants from the letters of the given word mathematics?Therefore, 30 words can be formed from the letters of the word DAUGHTER each containing 2 vowels and 3 consonants. Note: A Permutation is arranging the objects in order.
How many words each containing 2 vowels and 3 consonants van be formed using 5 vowels and 8 consonants?So, total number of words = 5C2× 17C3×5! =816000.
How many 5 letter words can be formed with 2 vowels and three consonants?There are 1440*10 = 14400 possible 5-letter “words” with two vowels and three consonants.
|